这是一个长达 13 周的解谜挑战，北京时间 12 月 10 日凌晨 01:00 起， Niantic 会在其论坛上
发布一个谜题，然后让玩家解谜，结果会是一个 Passcode ，兑换后可获得 Media 一个。
C:ptslashsofourtwominushyphenzrotwohyphenaltwoothree
A: rTLLlqZAgNgnYxlFakrMkvDxugedRGbjUAFtyEgeZywqVXtzgEnRxanrAWfJqtKHxeUcwmTgyIaeVONgeAGlHgrTtpMxtyOmoPksyfxCQgaIZFbiQwpRialUMqseQtIkpheBNsNfcTNnMFmeUcgAwsPhkgDrSNQhoGOXjEwsxOQrgMVFrLAomFLSzDnlnOchGbfijvOTcePWIerXvhBsjvGDngeZyXybzsEPyXxzMFdAepIzdlvguWuneBnrCfxrRPtLuGQTeOksaNmmFgzstgUTyiGGVrbRbuTgzrUMcniWsGgnxrLJuAfqKCu:fz
B: StmjkLSrryIIZUEJDuUfsBFBCuEeqiBGwgHNqntTGYPuuECVcpdhNzVGIeCTRTmCXfzNsKrBsnnSutMELFqIqRsczUXBsLZVcxVsAoGCeAsjEtvYdIzuSNtnLOIdsjraPtBeaacvPAgVbNGiwtUgoJBMAdcenTtvYYunbnuIXestUIbNWKrEdeYiCpdYacBuatLXeSqczAQfTPjrrUduYGWqtBaytxAsQdhralsYewqplTAApKRmPIFBRIAgrnXKqbRZRMvCTbHTssJXGWrDuPUhVQlcDEidJXxYqRSrnRwbfqRsMTbnkmKdvjt:jk
按照
slash = /, four = 4, two = 2, minus = -, hyphen = — three = 3
来转换字符串 C ，可得：
Google 搜索了一下，发现是一种催化剂。
Pt / SO42− - ZrO2 - Al2O3
如果把字符串 A 的大小写分别转换成 A 和 B ，即为：
ABBBAABBABAABAABAAABAABAAAAABBAABBBAABAABAAABBAAABABAAAABBABAABBAABAAABAABAABBBAABBABAABAABAAABAABAAAAABBAABBBAABAABAAABBAAABABAAAABBABAABBABBAABAABAABAAABABBBAABBBABAAABBAABBBABBAABBBABAAABAABAAAAABBAABBBAABAABAAABBAAABABAAAABBABAABBABAABAAAAAABAAABAABAAABBABABBBABAAABAABAAAAABBAABBBAABAABAAABBAAABABAAAABBABAABBA
再以此来做 Bacon 解谜，即为：
oneredherringisoneredherringzeroortworedherringsarenoredherring
分一下词得到一句话：
One Red herring is one red herring, zero or two red herrings are no red herring.
以字符串 C 为 key ，将字符串 A 做 Vigenere 解谜（忽略大小写），可得：
catalysisistheprocessofincreasingtherateofachemicalreactionbyaddingasubstanceknownasacatalystwhichisnotconsumedinthecatalyzedreactionandcancontinuetoactrepeatedlybecauseofthisonlyverysmallamountsofcatalystarerequiredtoalterthereactionrateinprincipleingeneralchemicalreactionsoccurfasterinthepresenceofacatalystbecau:ui
以上述字符串为 key ，将字符串 B 做
Beaufort 解谜（忽略大小写），可得：
khhrbnarbkklikliliknanahlinakkhhknarbnalihlinaknalikrbhnaklihhrblihnakkrbnakkrbklikkklirbrbrblinaknananaknalilikklikknanakrblinanahknalinahhnanarbknarbhrbnanalinahrbnakhknanarbrbhrbnakklinaknanahrbkkrblinalinaknaklinananahrbrbknarbkkrblilinahrbnakknananahhkklinanahkklikklirblinakkkhrbnakkkhrbnanalinaklihhklihrbhrb:ly
除去结尾冒号及之后的部分，可以发现前面的部分都是第 1 族（氢和碱金属）元素，即：
氢, H 锂, Li 钠, Na 钾, K 铷, Rb
那么按顺序
H = 1, ... Rb = 5
来转换，即为：
41153544242243312344114353212343245134211521344534454244425552343334322442443345233143231133543515332315341433551534423433154452323434233315543544522315344333114423314424425234441534441533234211421515
将这一串数字做 Polybius 解谜：
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1
|
2
|
3
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4
|
5
|
|
1
|
A
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B
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C
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D
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E
|
|
2
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F
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G
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H
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I/J
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K
|
|
3
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L
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M
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N
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O
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P
|
|
4
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Q
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R
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S
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T
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U
|
|
5
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V
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W
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X
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Y
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Z
|
可得：
QEPTIGSLHTASXFHSIVOFEFOUOURTRZWONOMIRTNUHLSHANYPENHEODNZEORONETWMOOHNEYPTWHEOSNATHLTIRWOTEOTENHRAREE
一个 100 字符的字符串。
每两个字符串一组后，再将奇数组和偶数组分别组成一个字符串，可得：
QEIGHTXFIVEFOURZNORTHLANENODEONEMONETWOSTHIRTEENAR PTSLASHSOFOURTWOMINUSHYPHENZROTWOHYPHENALTWOOTHREE
可以发现第二个字符串和字符串 C 是一样的，所以偶数行确实没用。
将奇数行按照
EIGHT = 8, FIVE = 5, FOUR = 4, ONE = 1, TWO = 2, THIRTEEN = 13
来转换，可得：
Q8X54ZNORTHLANENODE1M12S13AR
按照 13AR 系列的 passcode 格式来分一下词，可得
Q8X54Z Northlane Node 1m12s 13AR
Google 搜索后得知，Node 是 澳大利亚乐队 Nourthlane 的一个专辑，也是其中的第 3 首音乐的标题。
而这首音乐的 1′12″ 的歌词为：
