推理能力超越博士专家？最新大模型OpenAI o1到底是如何思考的？

用户

oyfjdnisdr rtqwainr acxz mynzbhhx -> Think step by step

Use the example above to decode:

oyekaijzdf aaptcg suaokybhai ouow aqht mynznvaatzacdfoulxxz

GPT

Let’s break this down step by step based on the example:

1. Example given:
• Input: oyfjdnisdr rtqwainr acxz mynzbhhx
• Output: Think step by step

By examining the words:
• The pattern involves selecting specific letters or transforming them.

2. Now, let’s decode the new phrase:
• Input: oyekaijzdf aaptcg suaokybhai ouow aqht mynznvaatzacdfoulxxz

Step-by-step decoding process:

Identify possible word divisions.

The first phrase might follow the same structure as the example. It seems like the input text could be broken into groups based on natural separations or patterns.

A possible division could be:

· oyekaijzdf

· aaptcg

· suaokybhai

· ouow

· aqht

· mynznvaatzacdfoulxxz

However, to make a meaningful decoding, I would need more context about the transformations or letter shifting that might be involved.

Could you provide any additional decoding rules or transformations used in this cipher?

用户

oyfjdnisdr rtqwainr acxz mynzbhhx -> Think step by step

Use the example above to decode:

oyekaijzdf aaptcg suaokybhai ouow aqht mynznvaatzacdfoulxxz

GPT

To decode the given ciphertext using the example provided, we’ll use the pattern identified in the example.

Ciphertext Example:

plainText

1 oyfjdnisdr rtqwainr acxz mynzbhhx

Decoded as:

plainText

1 Think step by step

Decoding Method:

1.Pair the letters in the ciphertext.

2.Convert each letter to its numerical position in the alphabet (A=1, B=2, …, Z=26).

3.Sum the numerical values of each pair.

4.Compute the average of the sum (divide by 2).

5.Convert the average back to a letter (1=A, 2=B, …, 26=Z).

Apply this method to the given ciphertext:

plainText

1 oyekaijzdf aaptcg suaokybhai ouow aqht

mynznvaatzacdfoulxxz

Break down the ciphertext into pairs:

1. First word: “oyekaijzdf”

a.Pairs: oy, ek, ai, jz, df

b.Decoded letters:

i.oy → (15+25)/2 = 20 → T

ii.ek → (5+11)/2 = 8 → H

iii.ai → (1+9)/2 = 5 → E

iv.jz → (10+26)/2 = 18 → R

c.df → (4+6)/2 = 5 → E

d.Decoded word: THERE

2.Second word: “aaptcg”

a. Pairs: aa, pt, cg

b.Decoded letters:

i.aa → (1+1)/2 = 1 → A

ii.pt → (16+20)/2 = 18 → R

iii.cg → (3+7)/2 = 5 → E

iv.Decoded word: ARE

3.Third word: “suaokybhai”

a.Pairs: su, ao, ky, bh, ai

b.Decoded letters:

i.su → (19+21)/2 = 20 → T

ii.ao → (1+15)/2 = 8 → H

iii.ky → (11+25)/2 = 18 → R

iv.bh → (2+8)/2 = 5 → E

v.ai → (1+9)/2 = 5 → E

c.Decoded word: THREE

4.Fourth word: “ouow”

a.Pairs: ou, ow

b.Decoded letters:

i.ou → (15+21)/2 = 18 → R

ii.ow → (15+23)/2 = 19 → S

c.Decoded letters: R’S

5.Fifth word: “aqht”

a.Pairs: aq, ht

b.Decoded letters:

i.aq → (1+17)/2 = 9 → I

ii.ht → (8+20)/2 = 14 → N

c.Decoded word: IN

6.Sixth word: “mynznvaatzacdfoulxxz”

a.Pairs: my, nz, nv, aa, tz, ac, df, ou, lx, xz

b.Decoded letters:

i.my → (13+25)/2 = 19 → S

ii.nz → (14+26)/2 = 20 → T

iii.nv → (14+22)/2 = 18 → R

iv.aa → (1+1)/2 = 1 → A

v.tz → (20+26)/2 = 23 → W

vi.ac → (1+3)/2 = 2 → B

vii.df → (4+6)/2 = 5 → E

viii.ou → (15+21)/2 = 18 → R

ix.lx → (12+24)/2 = 18 → R

x.xz → (24+26)/2 = 25 → Y

c.Decoded word: STRAWBERRY

Final Decoded Message:

PlainText

1 THERE ARE THREE R'S IN STRAWBERRY

Answer:

THERE ARE THREE R’S IN STRAWBERRY